x^2+18x-2520=0

Solution for x^2+18x-2520=0 equation:

x^2+18x-2520=0

a = 1; b = 18; c = -2520;
Δ = b2-4ac
Δ = 182-4·1·(-2520)
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-102}{2*1}=\frac{-120}{2}
=-60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+102}{2*1}=\frac{84}{2}
=42
$